$$A=\left \{x\in \Bbb R :x<\dfrac{2}{x} \right \}.$$
a) $\sup A = -1$ since $\max A=-1;$
b) $\inf A$ does not exist since $A$ is not bounded below.
Is this the only justifications? Can anyone check if this is correct?
$$A=\left \{x\in \Bbb R :x<\dfrac{2}{x} \right \}.$$
a) $\sup A = -1$ since $\max A=-1;$
b) $\inf A$ does not exist since $A$ is not bounded below.
Is this the only justifications? Can anyone check if this is correct?
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Hint:
If $A:=\{x\in\mathbb R\mid x<\frac2{x}\}$ then $$A=(-\infty,-\sqrt2)\cup(0,\sqrt2)$$