find the area of a surface of revolution about x-axis : arctanh x^2

Question

I want to calculate the area of surface of revolution about x-axis.. function is $y=f(x)=\tanh^{-1}x^2$. And area, A=$2\pi \int_{-1}^1 f(x)\sqrt{1+f'(x)^2} dx$ and $f'(x)=\frac{2x}{1-x^2}$ and $\tanh(x)=\frac{1}{2}\ln \frac{1+x^2}{1-x^2}$. I try to calculte this one.. but not easy. Help me.