$\ {(1 − x^{14})\over (1 − x)}$
My thought was:
$\ (1-x^{14})\over (1-x)$ $\ = (1 - x^{14}) ∑ x^n$ $\ = ∑ [x^n - x^{n+14}]$
But I'm not sure if I'm on the right path?
$\ {(1 − x^{14})\over (1 − x)}$
My thought was:
$\ (1-x^{14})\over (1-x)$ $\ = (1 - x^{14}) ∑ x^n$ $\ = ∑ [x^n - x^{n+14}]$
But I'm not sure if I'm on the right path?
HINT: $\frac{1-x^{p+1}}{1-x}=1+x+x^2+x^3+...+x^p$ (is called the "Geometric series") for arbitrary number $p$.