Given $f(x) = 3x^2 - 4x + 5$
what are the constants a, b, c if $f(x)$ was written in the form:
$a(x-b)^2 + c$
Given $f(x) = 3x^2 - 4x + 5$
what are the constants a, b, c if $f(x)$ was written in the form:
$a(x-b)^2 + c$
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$$3x^2-4x+5 = a(x-b)^2+c \\$$
$$3x^2-4x+5 = ax^2-2abx+b^2+c \\$$
So, it has to be:
$$a=3,\\-2ab=-4,\\b^2+c=5$$
or:
$$a=3, b=\frac{2}{3}, c=\frac{41}{9}.$$