The vectors v1 = ($\frac{3}{7}$, $\frac{6}{7}$,$\frac{−2}{7}$), v2 = ($\frac{−2}{7}$, $\frac{3}{7}$, $\frac{6}{7}$) and v3 = ($\frac{6}{7}$,$\frac{−2}{7}$, $\frac{3}{7}$) form an orthonormal basis of ℝ$^3$. Find the coordinates of the following vectors with respect to this basis.
(i) (1,0,0)
(ii) (2, N+10, 1)
I am wondering is there anyway I can find the coordinates without using reduced row form? For vectors in ℝ$^2$ you can use the dot product and a formula but I am not sure if that works for vectors in ℝ$^3$?
Any advice would be greatly appreciated.
If $v\in\Bbb R^3$, then$$v=(v.v_1)v_1+(v.v_2)v_2+(v.v_3)v_3.$$So, since, for instance,$$(1,0,0).v_1=\frac37,\ (1,0,0).v_2=-\frac27\text{, and }(1,0,0).v_3=\frac67,$$you have$$(1,0,0)=\frac37v_1-\frac27v_2+\frac67v_3.$$