This is what is given: $f '(x)=y=4x-5$
Find: the function, $f(x)$, of which $f '(x)$ is the derivative of.
In general:
$$\int \:\frac{d}{dx}\left(f\left(x\right)\right)dx=F\left(x\right)+constnat$$
In your case:
$\int \:\left(4x-5\right)dx=F\left(x\right)+constant$
Can you find $F(x)$?
your $f(x)= 2x^2-5x +C$ is unique up to a constant $C$.
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In general:
$$\int \:\frac{d}{dx}\left(f\left(x\right)\right)dx=F\left(x\right)+constnat$$
In your case:
$\int \:\left(4x-5\right)dx=F\left(x\right)+constant$
Can you find $F(x)$?