Find the indefinite integral
$$\int\frac{(x+1)e^x}{x(1+xe^x)}dx$$
I feel like this function does not have an anti-derivative in the form of elementary functions.
Find the indefinite integral
$$\int\frac{(x+1)e^x}{x(1+xe^x)}dx$$
I feel like this function does not have an anti-derivative in the form of elementary functions.
On
As written, you're correct. However, I suspect that it is supposed to be $$\int\frac{(x+1)e^x}{1+xe^x}\,dx,$$ which does have a nice antiderivative family, as the numerator is the derivative of the denominator.
On
You're entirely correct that the posted problem has no elementary antiderivative; you can easily confirm this using Wolfram Alpha.
However, if perchance your problem has a typo in it, and you meant to post:
$$\int\frac{(x+1)e^x}{(1+xe^x)}dx$$
Then note that with
$\;u = 1 + xe^x,\;$
$\;du = xe^x + e^x = (x+1)e^x$,
thus giving us an integral of the form $$\int \dfrac {du}{u} = \ln |u| + C = \ln|1 + xe^x| + C$$
You're right: Maple confirms that it does not have an elementary antiderivative.