for $125$ mod $13$ and $-43$ mod $7$
$13$ goes into $125$ $9$ times with a remainder of $8$
$7$ goes into $-43$ $6$ times with a remainder of $1$
So the least residues are $8$ and $1$(possibly $-1$)? Is it really that easy?
for $125$ mod $13$ and $-43$ mod $7$
$13$ goes into $125$ $9$ times with a remainder of $8$
$7$ goes into $-43$ $6$ times with a remainder of $1$
So the least residues are $8$ and $1$(possibly $-1$)? Is it really that easy?
$-43=-7\times7+6,$ so $-43\bmod 7=6.$