A sequence is recursively defined sequence.
$u_{n+1} = \frac{n}{n+1} u_{n}$, where $u_{1} = 1$
From the monotonic bounded theorem, one can show that a limit for this sequence exists. How to compute the limit?
A sequence is recursively defined sequence.
$u_{n+1} = \frac{n}{n+1} u_{n}$, where $u_{1} = 1$
From the monotonic bounded theorem, one can show that a limit for this sequence exists. How to compute the limit?
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Note that $(n+1)u_{n+1}=nu_n$ so that the sequence $(n u_n)_n$ is constant, thus equal to its first term $u_1$.
Therefore $u_n=\frac{u_1}{n}$ and $\lim_n u_n = 0$.