A team of $6$ people is to be selected from $8$ men and $4$ women. Find the number of different teams that can be selected if:
(i) there are no restrictions, (I solved this using ${n\choose r}=\frac{n!}{r!(n-r)!}$ the answer is $924$.)
(ii) the team contains all $4$ women.
How do i solve part (ii)?
Four out of $6$ positions are filled by the four women, leaving an all-men pool of eight. Since the women have been assigned to four of the six positions, there are only $2$ remaining spots to fill, out of $8$ men. $$\binom{8}{2}$$