This seems too easy, so i might be wrong.
The parametric equations of a line consist of a point on the line and a vector parallel to the line.
If the vector $u$ spans the line, then we can use this vector as the parallel vector. The point $(0,0,0)$ will be on the line so the parametric equations would be:
$ x = 3t \\
y = -2t \\
z = 5t
$
Is that right? there is no answer in the back of the book for this one. Thanks.
Yes, that is right. Your argument is correct.