$a$ and $b$ are coprimes, so $\gcd(a, b) = 1$. Find the values of $\gcd(3a - b, 2a + b)$.
Tried to use Bezout's identity, but I am totally stuck. Any hint?
$a$ and $b$ are coprimes, so $\gcd(a, b) = 1$. Find the values of $\gcd(3a - b, 2a + b)$.
Tried to use Bezout's identity, but I am totally stuck. Any hint?
If $d$ divides $A$ and $B$, then $d\mid A+B$.
So in your case, a divisor of $3a-b$ and $2a+b$ divides
$$3a-b+2a+b=5a.$$
More generally, if $d$ divides $A$ and $B$, then $d\mid uA+vB$.
So you also have
$$d\mid 2(3a-b)-3(2a+b)=-5b.$$
So $d\mid 5$ since $a$ and $b$ are coprimes.
So the gcd you are looking for is $5$ or $1$.