axis of symmetry y = 9, directrix x = 24, vertex on the line 3y −5x = 7
I've already researched for any similar problem like this but so far I found none. "vertex on the line 3y-5x=7" confuses me but I'm fine with the rest.
axis of symmetry y = 9, directrix x = 24, vertex on the line 3y −5x = 7
I've already researched for any similar problem like this but so far I found none. "vertex on the line 3y-5x=7" confuses me but I'm fine with the rest.
The axis of symmetry in this case is the y coordinate of the vertex. The vertex also lies on the line $3y-5x=7$
Therefore $$3(9)-5x=7$$ and on... $$27-5x=7$$
$$-5x=-20$$
$$x=4$$
So the vertex is $(4,9)$
You said you're fine with everything else so the question can be simplified to: Find the equation of the parabola with directrix $x=24$ and vertex $(4,9)$