A = {a ln a: a ∈ Q, a ≥ 0}.
I am stuck on this question. I started by letting f(a) = a ln a
Then solving for f'(a) = ln(a) + 1
Sup(A) = + infinity
I am not sure how to find Inf(A), Max(A), Min(A)
A = {a ln a: a ∈ Q, a ≥ 0}.
I am stuck on this question. I started by letting f(a) = a ln a
Then solving for f'(a) = ln(a) + 1
Sup(A) = + infinity
I am not sure how to find Inf(A), Max(A), Min(A)
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ln(a) + 1 = 0
ln(a) = -1
$a = e^{-1}$ would be an extrema but f is only defined on rationals. And the extrema would be $e^{-1}ln(e^{-1}) = -e^{-1}$
f''(a) = 1/a. So $f''(e^{-1}) = e > 0$ so there would be a local minimum at a = $e^{-1}$.
The is no point of minima but at all rational less than $e^{1} f are decreasing and at points higher it is increasing.
Although A is bounded below by $ -e^{-1}$, A has no minimum element.