A rectangle has sides of length $x-3$ units and $ax^2+bx+c$ units,where $a,b,c \in \mathbb Z$.
The area of the rectangle is $2x^3-13x^2+25x-12$ square units.
Find the value of $a,$ the value of $b$ and the value of $c.$
Diagram How would I answer this?
Area of rectangle is $l\cdot b$
So, $$(x-3)(ax^2+bx+c) = 2x^3-13x^2+25x-12$$
Multiply and compare like powers of $x$