I have an inequality of the kind $\dfrac{(1-a)}{b} > \dfrac{c+d}{c~ d}$ subject to the condition that $0 < c\leq 1, 0 < d \leq 1, a > 0 , b > 0 $.
How could I possibly find the values of $a, b, c, d$ that will satisfy the above condition ?
My attempts: $\dfrac{1-a}{b} \geq 2$. This leads to $2b + a < 1$. This can be solved to find the values of $a$ and $b$. But $c$ and $d$ are not easy to evaluate.
Any suggestions to solve the same would be of great help.
Thanks in advance.