Find the volume of water that will remain in the container below after tilting it $45$ degrees

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A container in the shape of a right circular cylinder is initially filled with water and resting on a flat, horizontal surface. However, the container was slowly tilted until the plane of its base $45^o$ with the horizontal plane. If the radius and height of the container measure $6$m and $8$m respectively, then the percentage of the volume of water that will remain in the container, in relation to the initial volume, is equal to? (Answer:$25 $%)

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I made the figure but I am not able to calculate the volume $BFC$

$V_t=\pi r^2h = \pi . 6^2.8 =288 \pi m^3$

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