Find the volume $V_y$ of the figure bounded by the lines $y=x^2,x=3,y=0$
I tried:
$$V_y=\pi \int_{0}^{3} x^4 dx=\pi \frac {3^5}{5}$$
Is this solution correct?
2026-03-25 01:18:29.1774401509
Find the volume $V_y$ of the figure bounded by the lines $y=x^2,x=3,y=0$
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Your derivation is correct for the volume for the solid of revolution around the $x$ axis by disk method.
Note that, for to the volume for the solid of revolution around the $y$ axis by disk method the set up would be
$$\pi \int_{0}^{9} (9-y)\, dy$$