Good time of day
I try to compute this integral $\displaystyle \int_{|z|=10} \frac{dz}{z^5+z+1}$
Can you help me please
My attempt is the following
I try to compute using residues. There are no poles. And consider residue at $\infty$. $\operatorname{Res}_{z=\infty}f(z)=0$
And as a result this integral is equal zero
I'm correct? or it's not true. I'm not sure about it.
It is false that there are no poles. There are always poles when you have a rational function which is not polynomial. However, it is true that if $|z|\geqslant2$, then $|z^5+z+1|\geqslant29>0$. Therefore, by Cauchy's theorem,$$\int_{|z|=R}\frac{\mathrm dz}{z^5+z+1}$$is independent of the choice of $R$, as long as $R\geqslant2$. So, since$$\lim_{R\to\infty}\int_{|z|=R}\frac{\mathrm dz}{z^5+z+1}=0,$$your integral is indeed $0$.