Find time-independent dynamical system equivalent to $x'=3x+(2-t)y$, $y'=xy-t$

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Given the continuous time dynamical system with the rule depending on time: $$x'=3x+(2-t)y\qquad y'=xy-t$$ create a new system which is equivalent to the above system for which the rule does not depend on $t$.


My solution so far: I recognize that this can be written in matrix for as in $Y'=AY$

|Y'| = |x'| = |3   2t| * |x|

       |y'|   |y -t/y|   |y|

I'm stuck here because I get the feeling my A shouldn't include any variables, so I tried to solve the DEs. I start with $y'=xy-t$:

$y'=xy-t$

$y'-xy=-t$

multiply by $u(t)=e^{-xt}$

d(ye^-(xt))/dt=-te^-(xt)

ye^-(xt)=[e^(xt)(1-xt)]/x^2

y=[e^(2xt)(1-xt)]/x^2

Then I'm stuck here but I'm pretty sure this isn't the way to go.