Find $2$ non-zero, $2 \times 2$ matrices, such that $\mathrm{rank}(A+B)=\mathrm{rank}(A)+\mathrm{rank}(B)$
I want to start from the identity matrix and work backwards, but I cant seem to cook up two matrices.
Find $2$ non-zero, $2 \times 2$ matrices, such that $\mathrm{rank}(A+B)=\mathrm{rank}(A)+\mathrm{rank}(B)$
I want to start from the identity matrix and work backwards, but I cant seem to cook up two matrices.
Copyright © 2021 JogjaFile Inc.
$\begin{pmatrix} 1 & 0 \\ 0 & 1 \end{pmatrix} = \begin{pmatrix} 1 & 0 \\ 0 & 0 \end{pmatrix} + \begin{pmatrix}? & ? \\ ? & ? \end{pmatrix}$