Find $u_3$ of recurrence relation $u_{n+1} = 0.2u_n + 9$ when only $u_5$ is known

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A sequence is defined by the recurrence relation $u_{n+1} = 0.2u_n + 9$, ${u_5 = 11}$. What is the value of ${u_3}$?

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I have not encountered a problem like this when only one value for n is provided. Normally I am given a couple of values for n and I can solve for u by solving simultaneous equations.

I thought I could put 11 into the equation and substitute 5 for n and find u.

${11 = 0.2u(5) + 9}$

=> ${u = 2}$

${u_3 = 0.2(3)(2) + 9} = 10.2$

But the answer is incorrect.

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Note that I have edited this answer since OP posted an image of the original question.


According to the recurrence relation, we have $u_5 = 0.2u_4 + 9$ and $u_4 = 0.2u_3 + 9$. Then we have $$\begin{align} u_5 &= 0.2u_4 + 9 \\ u_5 &= 0.2(0.2u_3 + 9) + 9 \\ (11) &= 0.2(0.2u_3 + 9) + 9 \\ 2 &= 0.2(0.2u_3 + 9) \\ 2/(0.2) &= (0.2u_3 + 9) \\ 10 &= 0.2u_3 + 9 \\ 1 &= 0.2u_3 \\ 1/(0.2) &= u_3 \\\\ 5 &= u_3 \end{align}$$