Find the volume of the solid obtained by rotating the region bounded by the given curves about the specified axis. $y = x^2, y = 1$; about $y = 2$
I know that the function will be rotated around the $x$-axis, but I am having problems with understanding getting the radius since the function rotates around $y = 2$. Any help would be appreciated. Thanks!
$x^2=1 \to x =\pm 1 \to V = \displaystyle \int_{-1}^1 \pi \left((2-x^2)^2 - (2-1)^2\right)dx$