Problem:
Two different sequences contains both a and b.
Sequence ..., -1, a, b, x,... is arithmetic.
Sequence ..., y, a, b; 12,5;... is geometric.
determine x and y.
I have been asked by a member of the mathoverflow to post here.
I have been going at this problem for several hours and haven't made any, in my opinion, real progress.
I welcome any solution to the problem :)
Let the common ratio of arithmetic progression be $d$.
$d=a+1=b-a=x-b$
Let the common ratio of geometric progression be $r$.
$r= \frac{a}{y}= \frac{b}{a}= \frac{12}{b}= \frac{5}{12}$
which gives $b= \frac{144}{5} \implies a= \frac{1728}{25} \implies y= \frac{20736}{125}.$
Now, the value of $b-a$ and $a+1$ do not match. Therefore, the question seems to be incorrect.