Finding a $9$-dimensional volume with three constraints - how to set up the integral?

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EDIT 1: I've made a major mistake in the calculations leading up to this question. The question should be regarded as "on hold" until further notice. Sorry for any inconvenience!

EDIT 2: I've updated my question. It it hopefully correct and more transparent now.


I have a real $3 \times 3$ matrix $A$ with entries $a_{ij}.$ I want to find the $9$-dimensional volume of the region satisfying the following three constraints:

  1. $\mathrm{tr} (A)<0,$
  2. $\det (A) > b \,\mathrm{tr}(A),$ and
  3. $\mathrm{tr}(A^TA)\leq 1,$

where $$b=a_{11}a_{22}+a_{11}a_{33}+a_{22}a_{33}-a_{12}a_{21}-a_{13}a_{31}-a_{23}a_{32},$$ and where the third constraint can also be written as $\sum_{i,j=1}^3 a_{ij}^2\leq1,$ i.e., the volume is bounded by the unit $9$-ball.

How should I set up the appropriate integrals for finding this volume? I'm at a bit of a loss here.

A numerical approach would also be of interest, but as I don't know how to set the integrals up in the first place, I don't know how to approach the problem numerically either.

My previous question provides some context.

Thank you.