Finding a basis for set of equations that passes through specific points and prove it subspace.

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Consider the vector space of functions $y=ax^2 + bx+ c$ for real constants a,b,c. To each function we can associate the vector $(a,b,c)^T$ . Find a basis of the set of these functions that passes through the points (x,y) = (1,2) and (3,4) . Is this set a subspace? What is its dimension?

Here is what I am thinking:

  1. Solving for the basis:
    2 = (1)a + (1)b + c
    3 = (4)a + (2)b + c

This can be written in the form of the following matrix:
$ \begin{bmatrix} 1 &4 \\ 1 & 2 \\ 1 & 1 \end{bmatrix} $ which can be reduced to: $\begin{bmatrix} 1 & 0 \\ 0 & 1 \\ 0 & 0 \end{bmatrix} $


Thus, our basis is:
$\begin{bmatrix} 1 \\ 0 \\ 0 \end{bmatrix} $ , $\begin{bmatrix} 0 \\ 1 \\ 0 \end{bmatrix} $

and it follows that the dimension is 2. I am going in the correct direction?

  1. How can prove this is a subspace?

Thanks !

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No. If you represent a quadratic polynomial by a column vector $\;\smash{\begin{bmatrix}a\\[-0.5ex]b\\[-1ex]c\end{bmatrix}}$,the system of linear equations you obtain is: $$\begin{bmatrix}1&1&1 \\4&2&1\end{bmatrix}\begin{bmatrix}a\\b\\c\end{bmatrix}=\begin{bmatrix}2\\1\end{bmatrix}$$ This is a inhomogeneous linear system. Its solutions are an affine subspace, with direction the vector subspace of solutions of the associated homogeneous linear system. As the matrix has rank $2$, this subspace has codimension $2$, i.e. dimension $3-2=1$.