Finding angle of a spigot that produces a parabolic fountain of water

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I am currently doing a math exploration and I need help in determining how to find the angle of a spigot that would maximize the area under a parabolic fountain. I thought of this topic to investigate, but I have no idea how to start! I know that this somehow involves integration.

I have trouble trying to find the angle and relating that to the water being ejected from the spigot.

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Presumably, the spigot is at ground height, so that the parabolic trajectory of the water is given by the parameterization $$ x(t) = (v_0\cos \theta )\\ y(t) = (v_0 \sin \theta)t -gt^2 $$ Solving for $t$ in terms of $x$ gives $$ t = \frac{x}{v_0 \cos\theta} \implies\\ y(x) = -\left(\frac{g}{v_0^2 \cos^2\theta}\right)x^2 + (\tan \theta) x $$ Now, find the value of $\theta$ that maximizes the area beneath this curve.