Suppose I have the ellipse $$ x^2 -2xy +4y^2 = 1 $$
How can I find the angle at which this ellipse is rotated?
I have tried to assign $x=\cos\theta, y=0.5\sin\theta$ but I don't know if that's the way
Suppose I have the ellipse $$ x^2 -2xy +4y^2 = 1 $$
How can I find the angle at which this ellipse is rotated?
I have tried to assign $x=\cos\theta, y=0.5\sin\theta$ but I don't know if that's the way
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Hint: look for the eigenvectors of \begin{pmatrix} 1 & -1 \\ -1 & 4 \end{pmatrix}