Find dy/dx by implicit differentiation
x^2-4xy+y^2=4
I know to take the derivatives of both sides, which would be:
d/dx[x^2-4xy+y^2]=0
I'm not sure if I did it right, but I then got:
2x-4*(xdy/dx)+y+2y(dy/dx)=0
I don't know where to go from here, or even if the previous step is correct. Please help!
Edit: I have followed the advice given and I ended up with:
(x-2y)/(2x-1)
However this was incorrect. Someone please tell me what I am missing here.
You are close! You forgot a coefficient on the $y$ term. You should have $$ 2x-4y-4x\frac{dy}{dx}+2y\frac{dy}{dx}=0 $$ Now you can solve for $\frac{dy}{dx}$ like any other variable.