Find equivalent pairs:
a. $\forall x(P(x)\land Q(x))$
b. $(\forall x(P(x))\land (\forall xQ(x))$
c. $\exists x(P(x)\land Q(x))$
d. $(\exists x(P(x))\land (\exists x Q(x))$
Are there rules for $\forall$ and $\exists$ distribution? should I use a logic table?
Our is it for example that for $\forall x(P(x)\land Q(x))$ we first set a $x$ and then "test" the statement and therefore it is equivalent to $\exists x(P(x)\land Q(x))$?
You can just translate your statements in English and see if that helps.
For all x, both P(x) and Q(x) are true.
For all x, P(x) is true and for all x, Q(x) is true.
There exists x (or there is/are some value(s) of x) for which both P(x) and Q(x) are true.
There exists x for which P(x) is true and there exists x for which Q(x) is true.
a,b are clearly equivalent. a is clearly not equivalent to c,d. d doesn't guarantee existence of x for which P(x) and Q(x) are simultaneously true. So d is not equivalent to c. To understand this let's use the following example:
P(x)= x is black, Q(x)= x is not black. If x is a bird, d suggests some birds are black and some are not but c suggests there is one or more bird that is simultaneously black and not black.