Finding index of sequence that satisfies given estimation

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How do I find the minimal $ n\in \mathbb{N} $ of sequence $ x_{n}=\frac{4+\sqrt{3n}}{3+\sqrt{3n}} $? Such that the estimation $ |x_{n}-1|<\frac{1}{10}, n\geqslant N $ holds? My idea was to find the $\min x_{n} $ and its index would be the solution but the [-1] part tells me, that it would be the correct way since it changes the estimation.