Given $g:\mathbb{R} \rightarrow \mathbb{R}$ is integrable and $f:\mathbb{R} \rightarrow \mathbb{R}$ is bounded, measurable, and continuous at $1$. Find $$\lim_{n \to \infty} \int_{-n}^n f\left(1+\frac{x}{n^2}\right)g(x)\,\mathrm{d}x.$$
I was thinking of using dominated convergence, but I can't find a dominator…
We have $\int_{-n}^n f\left(1+\frac{x}{n^2}\right)g(x)\,\mathrm{d}x= \int_{\mathbb R} 1_{(-n,n)} f\left(1+\frac{x}{n^2}\right)g(x)\,\mathrm{d}x$.
Now let $f_n(x):=1_{(-n,n)} f\left(1+\frac{x}{n^2}\right)g(x)$.
If $x \in \mathbb R$, then there is $N$ such that $x \in (-n,n)$ for all $n>N$, hence
$f_n(x) = f\left(1+\frac{x}{n^2}\right)g(x)$ for all $n>N$,thus
$f_n(x) \to f(1)g(x)$.
Can you proceed ?