$$\lim_{n\rightarrow \infty}\bigg(1+\sum^{n}_{r=1}\frac{2}{\binom{n}{r}}\bigg)^n$$
solution i try
$$\bigg(1+\frac{2}{n}\bigg)^n<\bigg(1+\sum^{n}_{r=1}\frac{2}{\binom{n}{r}}\bigg)<\bigg(1+\frac{2}{n}+\frac{2}{\binom{n}{2}}+\cdots +\frac{2}{\binom{n}{1}}+2\bigg)^n$$
I am struck here. did not know how to solve it . help me to do that problem . Thanks
You can find the limit of the sums of reciprocals of binomial coefficents on this MSE page:
So, for your limit we have $$1+\sum^{n}_{r=\color{blue}{1}}\frac{2}{\binom{n}{r}} \stackrel{n\rightarrow \infty}{\longrightarrow}3 \Rightarrow \lim_{n\rightarrow \infty}\bigg(1+\sum^{n}_{r=1}\frac{2}{\binom{n}{r}}\bigg)^n = +\infty$$