Finding limits of rational logarithmic functions

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How to calculate $$\lim\limits_{x\to 1}\frac{\ln (1+x(x-2))}{x(x-2)}=∞$$

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Hint:

Observe that

$$\log(1+x(x-2))=\log(x-1)^2=2\log|x-1|$$

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Well the numerator goes to $-\infty$ because $1+x(x-2)\to 0$ while the denominator goes to $-1$ and the fraction has $+\infty$ as à limit when $x\to 1$