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Kind of a strange one, I believe the first one would be a matrix of 0 1 and 1 0 yet I can't find a way to compute these mathematically, but rather through trial and error.
Hint: Let $e_i$ be the vector whose $i$-th coordinate is $1$ and all other coordinates are $0$. For a compatible matrix $M$, what is $Me_i$?
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We can for instance answer question b) by noting that
$$
\pmatrix{y+z\\x+z\\x+y} =
\pmatrix{0\cdot x + 1 \cdot y + 1 \cdot z\\
1 \cdot x + 0 \cdot y + 1 \cdot z\\
1 \cdot x + 1 \cdot y + 0 \cdot z} =
\pmatrix{0&1&1\\1&0&1\\1&1&0}\pmatrix{x\\y\\z}
$$
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Hint:
For a), swapping row $i$ and row $j$ in a matrix amounts to left multiply it by the unit matrix, with rows $i$ and $j$ swapped.
For b), denoting $e_1,e_2,e_3$ the canonical basis, you have
$$Ae_1=e_2+e_3,\quad Ae_2=e_3+e_1,\quad Ae_3=e_1+e_2.$$
Same method for c).
Hint: Let $e_i$ be the vector whose $i$-th coordinate is $1$ and all other coordinates are $0$. For a compatible matrix $M$, what is $Me_i$?