Finding norm of b given ||a||, ||a-b||, and ||a+b||?

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Let $a$ and $b$ be vectors such that $||a|| = 5$, $||a+b|| = 7$, and $||a-b|| = 9$. Find $||b||$.


What I've Tried: ( assuming * $=$ using a dot product) I did some rearranging by using the difference of the $||a+b||$ and $||a-b||$ terms, and found that $a * b = -8$. However, I'm unsure on how to proceed from here to get ||b||. Any help would be greatly appreciated!