Just a puzzle.
\begin{matrix}
2 & 9 & ? \\
11 & 33 & 66 \\
8 & 3 & 27 \\
\end{matrix}
The options are $35$, $40$, $45$, $55$.
$45$ is false.
I thought the answer was $15$ since they are of the form $3a + b = c$, but there isn't a $15$.
EDIT: It's not a problem from a math test so I think that the pattern (if there is one at all!) should be an "easy" one.
EDIT again: My friend said he was not sure if 45 is wrong. Maybe he is wrong on another problem. I think 45 is the right answer!
2026-03-27 06:15:35.1774592135
Finding pattern
212 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail At
2
The sum of all digits of each row is always 20.
Second row: $1+1+3+3+6+6=20$
Third row: $8+3+2+7=20$
Then:
First row: $2 + 9 +a +b = 11+a+b = 20 \Rightarrow a+b = 9$
where $10a + b$ is the number to be placed in the position $(1,3)$.
This is only possible if the number to be placed is $45$; in fact $a=4, b=5$ and $a+b=9$.