My recurrence relation is:
$$f(n)=(2n-3) f(n-1) -x^2 f(n-2)$$
Where
$$f(-1)=1$$ $$f(0)=0$$ $$f(1)=-x^2$$ $$f(2)=f(1)$$ $$f(3)=-x^2 (3-x^2)$$
And it gets more complicated from there
My recurrence relation is:
$$f(n)=(2n-3) f(n-1) -x^2 f(n-2)$$
Where
$$f(-1)=1$$ $$f(0)=0$$ $$f(1)=-x^2$$ $$f(2)=f(1)$$ $$f(3)=-x^2 (3-x^2)$$
And it gets more complicated from there
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