how is the method for finding series rep when you have constant in numerator (and variable)
couldnt find anything when searching or in my mathbook
question: express (3+x)/(1+x) in terms of (x-1)^k
i know that you are supposed to get the expression in a form of a/(1-r), but now i have "r" also in numerator
Help is very appreciated!
$$\frac{x+3}{x+1}=1+\frac{2}{x+1}=1+\frac{2}{2+x-1}=1+\frac{1}{1+\frac{(x-1)}{2}}$$
Then by the geometric series you have
$$\frac{x+3}{x+1}=1+\sum_{n=0}^{\infty}(-1)^n(\frac{x-1}{2})^{n}$$
which converges when $|x-1|<2$.