Finding the conjugacy classes of $S_{3}$

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I'm having difficulty in understanding how the conjugacy classes are calculated in $S_{3}$.

I know they are $\{e\}, \{(12),(13),(23)\}$ and $\{(123),(132)\}$ but do not know how to show for the latter two.

For $(12)$ in $S_{3}$, to find the conjugacy class, I know any conjugate will have the form $(g(1) g(2))$ where $g$ is the conjugating element. But the notes I have go on to say this: $(12)^{(23)} = ((23) · 1 (23) · 2) = (13)$ and $(12)^{(123)} = (23)$.

I can't understand why these calculations are done and what they mean and wondered if anyone could explain what is happening in this line

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I'm not sure what the caclulations are done, but the notation $(12)^{(23)}$ means that $(12)$ is conjugated by $(23)$, i.e. $(12)^{(23)} = (23)(12)(23)^{-1}$. I guess you can perform the composition of the cycles now and determine the value.

On the other hand in $S_n$ we have that two elements are conjugates iff they have the same kind of disjoint cycles. This means that the elements of the form $(a_1,a_2)$ are in one conjugacy class, while $(a_1,a_2,a_3)$ are in other.