Finding the correlation function of the output process at zero and checking if it is WSS

32 Views Asked by At

Assume two systems for which the following differential equations hold between their input and output signals.

$$a \dfrac{dv(t)}{dt}+b v(t)=x(t)$$

$$\dfrac{dy(t)}{dt}=v(t)u(t)$$

Also, assume that the input process $x(t)$ is white Gaussian noise (with mean zero) such that its correlation function is $R_x(\tau)=2b \delta(\tau)$ where $a,b$ are constants.

a) Calculate the value of the correlation function of the output process at zero, $R_y(0)$

b) Is $y(t)$ a WSS process?

So, this is how I imagine this question could be solved: 1. calculate $R_y$. Then measure it on $0$. (How? I do not know). To prove that a process is WSS (wide-sense stationary), I should prove that its mean (in this case $\mathbb{E}\{y(t)\}$ is a fix number like $\eta$ and prove that its autocorrelation only depends on $\tau=t_1-t_2$ (in other words, $\mathbb{E}\{y(t+\tau)y^*(t)\}=R(\tau)$). Since $\tau$ is actually the distance between $t$ and $t+\tau$, we would write $R(\tau)$ like this: $$R(\tau)=\mathbb{E}\{y(t+\frac{\tau}{2})y^*(t-\frac{\tau}{2})\}$$

However, I am new to all of these concepts and do not know how to do all of the things I mentioned. An answer with a little bit of detail would be very nice of you. Thanks in advance.