EDIT: Method $1$ is false, as pointed out by Hetebrij.
If it is night, how would one find the height of the building?
By assuming I am trying to find the height of a building at night, I am assuming that the building (or anything else) casts no shadow, so one cannot use similarities between triangles to find the height.
Also, assume that your only method of measurement is a ruler whose length is only $6.5$ meters and a clock.
Note that you cannot borrow (or steal) the blueprints for the building, and that all floors have different heights.
Here are several feasible methods that I have thought of.
$1.$ Using the Speed of a Elevator
This method assumes that there is one floor that is less than $6.5$ meters tall, and that there is a elevator.
Ride the elevator to see how long it takes to move $1$ floor. Say it took $a$ seconds. Then calculate the height of the room, which $h$m.
Ride the elevator from bottom to top. Say it took $b$ seconds. Then the height of the building would $\frac{b}{a} \times h$(m).
$2.$ Drop a ball from the Building
After calculating the time it takes for all ball to drop down of a building, use that $t=\sqrt{\frac{2h}{g}}$.
This assumes, of course, that there is no air resistance. Further methods concerning a falling body with air resistance are discussed here.
I cannot think of any other methods for finding the height of a transparent building. What are other methods that one can calculate it?

You can take something, say a ball (or maybe something bigger for practical purposes) to the rooftop. It'll cast a shadow. Then, you can use the triangle rules to find the height. Not too smart, but works. ;)