I'm trying to get a better understanding of linear codes, so I decided to work on problems from various textbooks. I'm having trouble understanding how to do this problem, and I was wondering if anyone can lead me in the right direction.
Problem The matrix $G = [I_{4} | A]$, where $$ G = \left[ \begin{array}{cccc|ccc} 1 & 0 & 0 & 0 & 0 & 1 & 1 \\ 0 & 1 & 0 & 0 & 1 & 0 & 1 \\ 0 & 0 & 1 & 0 & 1 & 1 & 0 \\ 0 & 0 & 0 & 1 & 1 & 1 & 1\end{array} \right] $$
is a genrator matrix in standard form for a $[7,4]$ binary code, denoted by $\mathcal{H}_3$. The parity check matrix for $\mathcal{H}_3$ is $$H = [A^{T} | I_{3}] = \left[ \begin{array}{cccc|ccc} 0 & 1 & 1 & 1 & 1 & 0 & 0 \\ 1 & 0 & 1 & 1 & 0 & 1 & 0 \\ 1 & 1 & 0 & 1 & 0 & 0 & 1 \end{array} \right]. $$
Find at least four information sets in $\mathcal{H}_3$. Find at least one set of four coordinates that do not form an information set. $\blacksquare$
The book defines an information set as follows: Given a $[n,k]$ linear code $\mathcal{C}$, a generator matrix for $\mathcal{C}$ is any $k \times n$ matrix $G$ whose rows form a basis for $\mathcal{C}$. For any set of $k$ independent columns of $G$, the corresponding set of coordinates forms an information set for $\mathcal{C}$.
Any help would be greatly appreciated since I've been staring at this for quite some time. Thanks!
Are you having trouble finding sets of 4 independent/dependent columns in $G$? or are you having trouble finding the corresponding set of coordinates, given the set of 4 independent columns?
If your problem is the first of the above, then the question is, do you know what it means for a set of vectors to be (linearly) independent, and how to test a set of vectors for this property? Can you see, for example, that the first 4 columns of $G$ are independent, while columns 2, 3, 4, 5 are not? There is a non-trivial linear combination of columns 2 through 5 giving the zero vector, namely, the 5th minus the sum of the other three; but there is no linear combination of the first 4 columns giving zero, other than the combination with all four coefficients being zero.
If this is not helpful, please consider editing more information into your question as to where exactly your difficulty is.