$$y = (3-x)(1+x)^2(1-x)^4$$
Hello,
how can I find the limit when $x \to \infty$ and when $x \to - \infty$?
Thanks.
2026-04-08 07:28:28.1775633308
Finding the limit at positive and negative infinity
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Well for $x\rightarrow +\infty$ you can say that $$y=(3-x)(1+x)^2(1-x)4 \sim (-x)(x)^2(-x)^4=-x^7\longrightarrow -\infty\mbox,$$ similarli for $x\rightarrow -\infty$ $$y\sim -x^7 \longrightarrow +\infty\mbox.$$