Finding Variance from Mean

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$$ E[X] = NQ $$

$$ X = \sum_{i=1}^N y_i^2$$

where $y_i$~$N(0,Q)$ and they are independent.

$$What \space is \space Var(X) ?$$

My understanding is:

$$ Var(X) = E[X^2]-E[X]^2 $$ But then what is $E[X^2]$ ?

I understand $X^2 = [ \space\sum_{i=1}^N y_i^2 \space ]^2$ But how do I compute $E[X^2] \space ?$

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There appears to be a typo. Since $X=Q^2\chi^2$, the first line should read $$E[X]=NQ^2$$ by using the expectation of a $\chi^2$ distribution. To find the variance, use the variance of the $\chi^2$ distribution: $$V[X]=V[Q^2\chi^2]=Q^4V[\chi^2]=2NQ^4$$