Finding when velocity is zero

Question

Given trajectory $s(t) = 2t^3 - 15t^2 + 36t + 2$ find, when velocity $v = 0$.

I'm doing this the following way: $$v = \frac{ds}{dt} = 6t^2 - 30t + 36.$$ Then making $v = 0$, i.e. $6t^2 - 30t + 36 = 0$ and solving that equation we get $t_1 = 2$ and $t_2 = 3$. I am right?

Answer 1

community wiki answer so that the question can be closed

Your solution is correct.