Let U be a subgroup of unipotents matrices(A - E is nilpotent). U is affine algebraic group. How to describe finite($\phi^n = id$) algebraic automorphisms $\phi$ of U such that $U^{\phi}$ is finite?
I solved this in case dim U = 1. In this case U = $\mathbb C$. Any automorphism is described by $a \in \mathbb C^*$. $\phi_a(x) = ax$.
$U^{\phi_a} = {0}$ therefore is finite. $\phi_a^n = \phi_{a^n} = 1$ so $a^n = 1$. So all finite automorphisms with finite $U^{\phi}$ are described by $a \in \mathbb C^*$, such that $a^n = 1$.
What to do if dim U > 1. Any help is appreciated.
I will give some hints.
Case (i) $U$ is commutative: then you can find vector space automorphisms of finite order. It is a matrix $A$ such that $A^n=I$, you can easily find reflection matrices.
Case (ii) Non-commutative. See if you can embed $U$ as a normal subgroup of some linear algebraic group. Typically, in some parabolic $P$ of a reductive group. Then any inner automorphism of finite order in $P$ will do. Take a Levi decomposition and an element of finite order in the Levi subgroup.