I keep forgetting it, so...
Given Banach spaces $X$ and $Y$.
Then it is wrong: $$\dim\mathcal{R}F<\infty:\quad F\in\mathcal{L}(X,Y)\implies F\in\mathcal{C}(X,Y)$$
Can I construct such?
I keep forgetting it, so...
Given Banach spaces $X$ and $Y$.
Then it is wrong: $$\dim\mathcal{R}F<\infty:\quad F\in\mathcal{L}(X,Y)\implies F\in\mathcal{C}(X,Y)$$
Can I construct such?
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Ok satisfactory enough:
Given the Hilbert space $\ell^2(\mathbb{N})$.
Extend to a Hamel basis: $$\mathcal{B}:=\{\delta_n:n\in\mathbb{N}\}\cup\{\beta,\beta',\ldots\}$$
Define an operator by: $$T(\delta_n):=n\quad(n\in\mathbb{N})$$ $$T(\beta):=0\quad(\beta,\beta',\ldots)$$
Then it is unbounded.