So I'm completely stumped with this one. Tried tackling it from a few different angles but getting nowhere. I have to figure out $a_1$ and the common difference of the sequence where the following two equation hold true.
$a_2+a_3+a_4=20\\ a_1*a_4=-20 $
HINT Let $d$ be the difference. Then, $a_2 = a_1+d$ and $a_3 = a_1+2d$. Can you write $a_4$ as a function of $a_1$ and $d$ and plug into both equations?
UPDATE
Correct, $a_4 = a_1+3d$ so the first equation becomes $$ 20 = a_2 + a_3 + a_4 = 3a_1 + 6d $$ and the second one is $$ a_1(a_1+3d) = -20 $$ and you can use the first equation to solve for $3d$ and plug into the second one: $3d=10-3a_1/2$, thus we get $$ a_1(a_1+10-3a_1/2) = -20 $$ Can you finish?