Cost: $C^2=x^2+96 \sqrt x+60$
Revenue: $892(x-5)^2+22R^2=18502$.
Find the marginal cost $dC\over dx$ at $x=5$
Cost: $C^2=x^2+96 \sqrt x+60$
Revenue: $892(x-5)^2+22R^2=18502$.
Find the marginal cost $dC\over dx$ at $x=5$
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Well, the function C does not depend on R so you can just ignore Revenue for now.
Cost is given as $C^2$ so you have to use implicit differentiation to find its derivative.
$$2C {dC \over dx} = {2x} + {96\over {2 \sqrt x}}$$
Then solve for ${dC \over dx}$ and plug in x = 5.